Base | Representation |
---|---|
bin | 10001011110100111001… |
… | …101100011000011100001 |
3 | 11020211020210211222201122 |
4 | 101132213031203003201 |
5 | 124134323403101423 |
6 | 2315440035342025 |
7 | 152530256636102 |
oct | 21364715430341 |
9 | 4224223758648 |
10 | 1201101222113 |
11 | 423425366611 |
12 | 174946451915 |
13 | 893567a5a20 |
14 | 421c28a43a9 |
15 | 2139b7138c8 |
hex | 117a73630e1 |
1201101222113 has 8 divisors (see below), whose sum is σ = 1293502156968. Its totient is φ = 1108701506304.
The previous prime is 1201101222059. The next prime is 1201101222121. The reversal of 1201101222113 is 3112221011021.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 273174784 + 1200828047329 = 16528^2 + 1095823^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1201101222113 - 218 = 1201100959969 is a prime.
It is a super-2 number, since 2×12011012221132 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1201101222091 and 1201101222100.
It is not an unprimeable number, because it can be changed into a prime (1201101222133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3512681 + ... + 3839417.
It is an arithmetic number, because the mean of its divisors is an integer number (161687769621).
Almost surely, 21201101222113 is an apocalyptic number.
1201101222113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1201101222113 is a deficient number, since it is larger than the sum of its proper divisors (92400934855).
1201101222113 is a wasteful number, since it uses less digits than its factorization.
1201101222113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 609523.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1201101222113 its reverse (3112221011021), we get a palindrome (4313322233134).
The spelling of 1201101222113 in words is "one trillion, two hundred one billion, one hundred one million, two hundred twenty-two thousand, one hundred thirteen".
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