12011020000013 has 4 divisors (see below), whose sum is σ = 12011038045440. Its totient is φ = 12011001954588.

The previous prime is 12011019999991. The next prime is 12011020000037. The reversal of 12011020000013 is 31000002011021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12011020000013 - 2¹⁴ = 12011019983629 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12011019999949 and 12011020000003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12011020000043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7984493 + ... + 9368786.

It is an arithmetic number, because the mean of its divisors is an integer number (3002759511360).

Almost surely, 2^{12011020000013} is an apocalyptic number.

It is an amenable number.

12011020000013 is a deficient number, since it is larger than the sum of its proper divisors (18045427).

12011020000013 is an equidigital number, since it uses as much as digits as its factorization.

12011020000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18045426.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 12011020000013 its reverse (31000002011021), we get a palindrome (43011022011034).

The spelling of 12011020000013 in words is "twelve trillion, eleven billion, twenty million, thirteen", and thus it is an aban number and an uban number.