12011125404035 has 8 divisors (see below), whose sum is σ = 14434453491120. Its totient is φ = 9594831652384.

The previous prime is 12011125404017. The next prime is 12011125404049. The reversal of 12011125404035 is 53040452111021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12011125404035 - 2¹⁸ = 12011125141891 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12011125403989 and 12011125404007.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1758580100 + ... + 1758586929.

It is an arithmetic number, because the mean of its divisors is an integer number (1804306686390).

Almost surely, 2^{12011125404035} is an apocalyptic number.

12011125404035 is a deficient number, since it is larger than the sum of its proper divisors (2423328087085).

12011125404035 is an equidigital number, since it uses as much as digits as its factorization.

12011125404035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3517167717.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 12011125404035 its reverse (53040452111021), we get a palindrome (65051577515056).

The spelling of 12011125404035 in words is "twelve trillion, eleven billion, one hundred twenty-five million, four hundred four thousand, thirty-five".