12011133102013 has 4 divisors (see below), whose sum is σ = 12290461778848. Its totient is φ = 11731804425180.

The previous prime is 12011133101987. The next prime is 12011133102203. The reversal of 12011133102013 is 31020133111021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12011133102013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12011133102613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139664338353 + ... + 139664338438.

It is an arithmetic number, because the mean of its divisors is an integer number (3072615444712).

Almost surely, 2^{12011133102013} is an apocalyptic number.

It is an amenable number.

12011133102013 is a deficient number, since it is larger than the sum of its proper divisors (279328676835).

12011133102013 is an equidigital number, since it uses as much as digits as its factorization.

12011133102013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279328676834.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 12011133102013 its reverse (31020133111021), we get a palindrome (43031266213034).

The spelling of 12011133102013 in words is "twelve trillion, eleven billion, one hundred thirty-three million, one hundred two thousand, thirteen".