Base | Representation |
---|---|
bin | 1010111011001001001101… |
… | …1011100000111110000111 |
3 | 1120112021000022122211220102 |
4 | 2232302103123200332013 |
5 | 3033242420204221203 |
6 | 41313511532154315 |
7 | 2346531532440410 |
oct | 256622333407607 |
9 | 46467008584812 |
10 | 12011202023303 |
11 | 3910a164577aa |
12 | 141ba2730899b |
13 | 69186142c442 |
14 | 2d74b963a807 |
15 | 15c68b5b8888 |
hex | aec936e0f87 |
12011202023303 has 16 divisors (see below), whose sum is σ = 13809844038144. Its totient is φ = 10233253994400.
The previous prime is 12011202023297. The next prime is 12011202023309. The reversal of 12011202023303 is 30332020211021.
It is an interprime number because it is at equal distance from previous prime (12011202023297) and next prime (12011202023309).
It is a cyclic number.
It is not a de Polignac number, because 12011202023303 - 26 = 12011202023239 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12011202023309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30710528 + ... + 31099178.
It is an arithmetic number, because the mean of its divisors is an integer number (863115252384).
Almost surely, 212011202023303 is an apocalyptic number.
12011202023303 is a deficient number, since it is larger than the sum of its proper divisors (1798642014841).
12011202023303 is a wasteful number, since it uses less digits than its factorization.
12011202023303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 415262.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 12011202023303 its reverse (30332020211021), we get a palindrome (42343222234324).
The spelling of 12011202023303 in words is "twelve trillion, eleven billion, two hundred two million, twenty-three thousand, three hundred three".
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