Base | Representation |
---|---|
bin | 1010111011001001101100… |
… | …0011110000000001011111 |
3 | 1120112021100020111022100001 |
4 | 2232302123003300001133 |
5 | 3033243200440324411 |
6 | 41313532343315131 |
7 | 2346534645351145 |
oct | 256623303600137 |
9 | 46467306438301 |
10 | 12011330011231 |
11 | 3910a81724a51 |
12 | 141ba6214baa7 |
13 | 691881ac2145 |
14 | 2d74cc635595 |
15 | 15c69794adc1 |
hex | aec9b0f005f |
12011330011231 has 16 divisors (see below), whose sum is σ = 12676517785600. Its totient is φ = 11349448770528.
The previous prime is 12011330011189. The next prime is 12011330011243. The reversal of 12011330011231 is 13211003311021.
12011330011231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12011330011231 - 27 = 12011330011103 is a prime.
It is a super-3 number, since 3×120113300112313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12011330011199 and 12011330011208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12011330021231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89234326 + ... + 89368828.
It is an arithmetic number, because the mean of its divisors is an integer number (792282361600).
Almost surely, 212011330011231 is an apocalyptic number.
12011330011231 is a deficient number, since it is larger than the sum of its proper divisors (665187774369).
12011330011231 is a wasteful number, since it uses less digits than its factorization.
12011330011231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146758.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 12011330011231 its reverse (13211003311021), we get a palindrome (25222333322252).
The spelling of 12011330011231 in words is "twelve trillion, eleven billion, three hundred thirty million, eleven thousand, two hundred thirty-one".
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