Base | Representation |
---|---|
bin | 10001011110101001000… |
… | …111001101000000111001 |
3 | 11020211100000212020100110 |
4 | 101132221013031000321 |
5 | 124134410034112101 |
6 | 2315443135054533 |
7 | 152531125002444 |
oct | 21365107150071 |
9 | 4224300766313 |
10 | 1201133113401 |
11 | 423441368a51 |
12 | 174955071449 |
13 | 89360290800 |
14 | 421c6c0665b |
15 | 2139e412cd6 |
hex | 117a91cd039 |
1201133113401 has 12 divisors (see below), whose sum is σ = 1734180353808. Its totient is φ = 739158838704.
The previous prime is 1201133113399. The next prime is 1201133113463. The reversal of 1201133113401 is 1043113311021.
It is not a de Polignac number, because 1201133113401 - 21 = 1201133113399 is a prime.
It is a super-2 number, since 2×12011331134012 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1201133133401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1184548915 + ... + 1184549928.
It is an arithmetic number, because the mean of its divisors is an integer number (144515029484).
Almost surely, 21201133113401 is an apocalyptic number.
It is an amenable number.
1201133113401 is a deficient number, since it is larger than the sum of its proper divisors (533047240407).
1201133113401 is a wasteful number, since it uses less digits than its factorization.
1201133113401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2369098872 (or 2369098859 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1201133113401 its reverse (1043113311021), we get a palindrome (2244246424422).
The spelling of 1201133113401 in words is "one trillion, two hundred one billion, one hundred thirty-three million, one hundred thirteen thousand, four hundred one".
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