Base | Representation |
---|---|
bin | 10001011110101001000… |
… | …111001101000000111000 |
3 | 11020211100000212020100102 |
4 | 101132221013031000320 |
5 | 124134410034112100 |
6 | 2315443135054532 |
7 | 152531125002443 |
oct | 21365107150070 |
9 | 4224300766312 |
10 | 1201133113400 |
11 | 423441368a50 |
12 | 174955071448 |
13 | 893602907cc |
14 | 421c6c0665a |
15 | 2139e412cd5 |
hex | 117a91cd038 |
1201133113400 has 48 divisors (see below), whose sum is σ = 3046510356840. Its totient is φ = 436775676800.
The previous prime is 1201133113399. The next prime is 1201133113463. The reversal of 1201133113400 is 43113311021.
It is a super-2 number, since 2×12011331134002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 272982599 + ... + 272986998.
Almost surely, 21201133113400 is an apocalyptic number.
1201133113400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1201133113400 is an abundant number, since it is smaller than the sum of its proper divisors (1845377243440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201133113400 is a wasteful number, since it uses less digits than its factorization.
1201133113400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 545969624 (or 545969615 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1201133113400 its reverse (43113311021), we get a palindrome (1244246424421).
The spelling of 1201133113400 in words is "one trillion, two hundred one billion, one hundred thirty-three million, one hundred thirteen thousand, four hundred".
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