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12011334434401 = 23737950599819
BaseRepresentation
bin1010111011001001101101…
…0100100111111001100001
31120112021100112211000210011
42232302123110213321201
53033243203103400101
641313533022204521
72346535031062531
oct256623324477141
946467315730704
1012011334434401
113910a84176165
12141ba63723741
136918829b04c3
142d74cd0674c1
1515c698021751
hexaec9b527e61

12011334434401 has 4 divisors (see below), whose sum is σ = 12011385271600. Its totient is φ = 12011283597204.

The previous prime is 12011334434383. The next prime is 12011334434471. The reversal of 12011334434401 is 10443443311021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12011334434401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12011334434471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25062531 + ... + 25537288.

It is an arithmetic number, because the mean of its divisors is an integer number (3002846317900).

Almost surely, 212011334434401 is an apocalyptic number.

It is an amenable number.

12011334434401 is a deficient number, since it is larger than the sum of its proper divisors (50837199).

12011334434401 is an equidigital number, since it uses as much as digits as its factorization.

12011334434401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50837198.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 12011334434401 its reverse (10443443311021), we get a palindrome (22454777745422).

The spelling of 12011334434401 in words is "twelve trillion, eleven billion, three hundred thirty-four million, four hundred thirty-four thousand, four hundred one".

Divisors: 1 237379 50599819 12011334434401