Base | Representation |
---|---|
bin | 1010111011001001101101… |
… | …0100100111111010100111 |
3 | 1120112021100112211000212202 |
4 | 2232302123110213322213 |
5 | 3033243203103400341 |
6 | 41313533022205115 |
7 | 2346535031062661 |
oct | 256623324477247 |
9 | 46467315730782 |
10 | 12011334434471 |
11 | 3910a84176219 |
12 | 141ba6372379b |
13 | 6918829b0548 |
14 | 2d74cd067531 |
15 | 15c69802179b |
hex | aec9b527ea7 |
12011334434471 has 2 divisors, whose sum is σ = 12011334434472. Its totient is φ = 12011334434470.
The previous prime is 12011334434383. The next prime is 12011334434501. The reversal of 12011334434471 is 17443443311021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011334434471 is a prime.
It is a super-3 number, since 3×120113344344713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011334439471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005667217235 + 6005667217236.
It is an arithmetic number, because the mean of its divisors is an integer number (6005667217236).
Almost surely, 212011334434471 is an apocalyptic number.
12011334434471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011334434471 is an equidigital number, since it uses as much as digits as its factorization.
12011334434471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 12011334434471 its reverse (17443443311021), we get a palindrome (29454777745492).
The spelling of 12011334434471 in words is "twelve trillion, eleven billion, three hundred thirty-four million, four hundred thirty-four thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •