1201134204331 has 4 divisors (see below), whose sum is σ = 1242552625200. Its totient is φ = 1159715783464.

The previous prime is 1201134204307. The next prime is 1201134204359. The reversal of 1201134204331 is 1334024311021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201134204331 - 2⁵ = 1201134204299 is a prime.

It is a super-2 number, since 2×1201134204331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1201134204296 and 1201134204305.

It is not an unprimeable number, because it can be changed into a prime (1201134204301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20709210391 + ... + 20709210448.

It is an arithmetic number, because the mean of its divisors is an integer number (310638156300).

Almost surely, 2^{1201134204331} is an apocalyptic number.

1201134204331 is a deficient number, since it is larger than the sum of its proper divisors (41418420869).

1201134204331 is an equidigital number, since it uses as much as digits as its factorization.

1201134204331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41418420868.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1201134204331 its reverse (1334024311021), we get a palindrome (2535158515352).

The spelling of 1201134204331 in words is "one trillion, two hundred one billion, one hundred thirty-four million, two hundred four thousand, three hundred thirty-one".