12012000043 has 4 divisors (see below), whose sum is σ = 12267574560. Its totient is φ = 11756425528.

The previous prime is 12012000037. The next prime is 12012000047. The reversal of 12012000043 is 34000021021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34000021021 = 233 ⋅145922837.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12012000043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12011999987 and 12012000032.

It is not an unprimeable number, because it can be changed into a prime (12012000047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127787188 + ... + 127787281.

It is an arithmetic number, because the mean of its divisors is an integer number (3066893640).

Almost surely, 2^12012000043 is an apocalyptic number.

12012000043 is a deficient number, since it is larger than the sum of its proper divisors (255574517).

12012000043 is an equidigital number, since it uses as much as digits as its factorization.

12012000043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255574516.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 12012000043 its reverse (34000021021), we get a palindrome (46012021064).

The spelling of 12012000043 in words is "twelve billion, twelve million, forty-three", and thus it is an aban number and an uban number.