Base | Representation |
---|---|
bin | 11011010011111110011101… |
… | …111111010111100111111111 |
3 | 120202022100201101211112220101 |
4 | 123103332131333113213333 |
5 | 111221021230224030413 |
6 | 1103250211110501531 |
7 | 34205245413651613 |
oct | 3323763577274777 |
9 | 522270641745811 |
10 | 120120001001983 |
11 | 35301674053114 |
12 | 115800893648a7 |
13 | 52043628a5118 |
14 | 2193ba6597343 |
15 | dd48e4757edd |
hex | 6d3f9dfd79ff |
120120001001983 has 8 divisors (see below), whose sum is σ = 121575680553600. Its totient is φ = 118669888103448.
The previous prime is 120120001001951. The next prime is 120120001001999. The reversal of 120120001001983 is 389100100021021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120120001001983 - 25 = 120120001001951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120120001001933) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1391619853 + ... + 1391706166.
It is an arithmetic number, because the mean of its divisors is an integer number (15196960069200).
Almost surely, 2120120001001983 is an apocalyptic number.
120120001001983 is a deficient number, since it is larger than the sum of its proper divisors (1455679551617).
120120001001983 is a wasteful number, since it uses less digits than its factorization.
120120001001983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2783326541.
The product of its (nonzero) digits is 864, while the sum is 28.
The spelling of 120120001001983 in words is "one hundred twenty trillion, one hundred twenty billion, one million, one thousand, nine hundred eighty-three".
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