12012001131133 has 4 divisors (see below), whose sum is σ = 12181184245728. Its totient is φ = 11842818016540.

The previous prime is 12012001131121. The next prime is 12012001131197. The reversal of 12012001131133 is 33113110021021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12012001131133 - 2²⁹ = 12011464260221 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12012001131133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012001132133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84591557191 + ... + 84591557332.

It is an arithmetic number, because the mean of its divisors is an integer number (3045296061432).

Almost surely, 2^{12012001131133} is an apocalyptic number.

It is an amenable number.

12012001131133 is a deficient number, since it is larger than the sum of its proper divisors (169183114595).

12012001131133 is an equidigital number, since it uses as much as digits as its factorization.

12012001131133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 169183114594.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 12012001131133 its reverse (33113110021021), we get a palindrome (45125111152154).

The spelling of 12012001131133 in words is "twelve trillion, twelve billion, one million, one hundred thirty-one thousand, one hundred thirty-three".