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1201202122011 = 3400400707337
BaseRepresentation
bin10001011110101101001…
…110011100110100011011
311020211111211201020100220
4101132231032130310123
5124140030220401021
62315454042131123
7152532623366643
oct21365516346433
94224454636326
101201202122011
11423477312161
121749741b0aa3
1389371672cc8
14421d204b523
15213a54e4cc6
hex117ad39cd1b

1201202122011 has 4 divisors (see below), whose sum is σ = 1601602829352. Its totient is φ = 800801414672.

The previous prime is 1201202121961. The next prime is 1201202122013. The reversal of 1201202122011 is 1102212021021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201202122011 - 27 = 1201202121883 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1201202122013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200200353666 + ... + 200200353671.

It is an arithmetic number, because the mean of its divisors is an integer number (400400707338).

Almost surely, 21201202122011 is an apocalyptic number.

1201202122011 is a deficient number, since it is larger than the sum of its proper divisors (400400707341).

1201202122011 is an equidigital number, since it uses as much as digits as its factorization.

1201202122011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400400707340.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 1201202122011 its reverse (1102212021021), we get a palindrome (2303414143032).

The spelling of 1201202122011 in words is "one trillion, two hundred one billion, two hundred two million, one hundred twenty-two thousand, eleven".

Divisors: 1 3 400400707337 1201202122011