Base | Representation |
---|---|
bin | 11011010011111110101011… |
… | …000011100011010000010010 |
3 | 120202022101021200022001210121 |
4 | 123103332223003203100102 |
5 | 111221022202332431002 |
6 | 1103250244541020454 |
7 | 34205254015063666 |
oct | 3323765303432022 |
9 | 522271250261717 |
10 | 120120220202002 |
11 | 3530177685a359 |
12 | 1158012a85472a |
13 | 5204399122687 |
14 | 2193bc77368a6 |
15 | dd4908b06237 |
hex | 6d3fab0e3412 |
120120220202002 has 8 divisors (see below), whose sum is σ = 180182334602700. Its totient is φ = 60059442001104.
The previous prime is 120120220201997. The next prime is 120120220202009. The reversal of 120120220202002 is 200202022021021.
It can be written as a sum of positive squares in 2 ways, for example, as 120116580372441 + 3639829561 = 10959771^2 + 60331^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×1201202202020023 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (120120220202009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333825177 + ... + 334184812.
Almost surely, 2120120220202002 is an apocalyptic number.
120120220202002 is a deficient number, since it is larger than the sum of its proper divisors (60062114400698).
120120220202002 is an equidigital number, since it uses as much as digits as its factorization.
120120220202002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 668099900.
The product of its (nonzero) digits is 128, while the sum is 16.
Adding to 120120220202002 its reverse (200202022021021), we get a palindrome (320322242223023).
The spelling of 120120220202002 in words is "one hundred twenty trillion, one hundred twenty billion, two hundred twenty million, two hundred two thousand, two".
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