Base | Representation |
---|---|
bin | 10001011110101101001… |
… | …111100011101001101111 |
3 | 11020211111212020222100112 |
4 | 101132231033203221233 |
5 | 124140030304142033 |
6 | 2315454052250235 |
7 | 152532626015546 |
oct | 21365517435157 |
9 | 4224455228315 |
10 | 1201202412143 |
11 | 4234774a0138 |
12 | 17497431097b |
13 | 89371745096 |
14 | 421d20c515d |
15 | 213a5550c48 |
hex | 117ad3e3a6f |
1201202412143 has 4 divisors (see below), whose sum is σ = 1218120756048. Its totient is φ = 1184284068240.
The previous prime is 1201202412119. The next prime is 1201202412149. The reversal of 1201202412143 is 3412142021021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1201202412143 - 26 = 1201202412079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201202412149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8459171846 + ... + 8459171987.
It is an arithmetic number, because the mean of its divisors is an integer number (304530189012).
Almost surely, 21201202412143 is an apocalyptic number.
1201202412143 is a deficient number, since it is larger than the sum of its proper divisors (16918343905).
1201202412143 is an equidigital number, since it uses as much as digits as its factorization.
1201202412143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16918343904.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1201202412143 its reverse (3412142021021), we get a palindrome (4613344433164).
The spelling of 1201202412143 in words is "one trillion, two hundred one billion, two hundred two million, four hundred twelve thousand, one hundred forty-three".
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