Base | Representation |
---|---|
bin | 11011010011111110110000… |
… | …011111000110111111000011 |
3 | 120202022101112000201221122221 |
4 | 123103332300133012333003 |
5 | 111221022344143443243 |
6 | 1103250301553511511 |
7 | 34205256202362520 |
oct | 3323766037067703 |
9 | 522271460657587 |
10 | 120120311312323 |
11 | 35301813229943 |
12 | 11580155272597 |
13 | 52043b1c72aca |
14 | 2193bd5892147 |
15 | dd4911b01bed |
hex | 6d3fb07c6fc3 |
120120311312323 has 16 divisors (see below), whose sum is σ = 145239168856320. Its totient is φ = 97046171875296.
The previous prime is 120120311312317. The next prime is 120120311312359. The reversal of 120120311312323 is 323213113021021.
It is not a de Polignac number, because 120120311312323 - 25 = 120120311312291 is a prime.
It is not an unprimeable number, because it can be changed into a prime (120120311352323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2292258661 + ... + 2292311062.
It is an arithmetic number, because the mean of its divisors is an integer number (9077448053520).
Almost surely, 2120120311312323 is an apocalyptic number.
120120311312323 is a deficient number, since it is larger than the sum of its proper divisors (25118857543997).
120120311312323 is a wasteful number, since it uses less digits than its factorization.
120120311312323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4584569946.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 120120311312323 its reverse (323213113021021), we get a palindrome (443333424333344).
The spelling of 120120311312323 in words is "one hundred twenty trillion, one hundred twenty billion, three hundred eleven million, three hundred twelve thousand, three hundred twenty-three".
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