Base | Representation |
---|---|
bin | 1010111011001100100011… |
… | …1101011100111011111011 |
3 | 1120112100022220120111011022 |
4 | 2232303020331130323323 |
5 | 3033301240112041443 |
6 | 41314141013253055 |
7 | 2346563016166226 |
oct | 256631075347373 |
9 | 46470286514138 |
10 | 12012100112123 |
11 | 39113373a4171 |
12 | 142003803418b |
13 | 691975506c47 |
14 | 2d7562a1a5bd |
15 | 15c6e0368e68 |
hex | aecc8f5cefb |
12012100112123 has 4 divisors (see below), whose sum is σ = 12079206816840. Its totient is φ = 11944993407408.
The previous prime is 12012100112119. The next prime is 12012100112317. The reversal of 12012100112123 is 32121100121021.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12012100112123 - 22 = 12012100112119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12012100142123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33553352090 + ... + 33553352447.
It is an arithmetic number, because the mean of its divisors is an integer number (3019801704210).
Almost surely, 212012100112123 is an apocalyptic number.
12012100112123 is a deficient number, since it is larger than the sum of its proper divisors (67106704717).
12012100112123 is an equidigital number, since it uses as much as digits as its factorization.
12012100112123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67106704716.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12012100112123 its reverse (32121100121021), we get a palindrome (44133200233144).
The spelling of 12012100112123 in words is "twelve trillion, twelve billion, one hundred million, one hundred twelve thousand, one hundred twenty-three".
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