Base | Representation |
---|---|
bin | 10001011110101101101… |
… | …100100011011000100111 |
3 | 11020211112101120011002000 |
4 | 101132231230203120213 |
5 | 124140034230410343 |
6 | 2315454523220343 |
7 | 152533050434253 |
oct | 21365554433047 |
9 | 4224471504060 |
10 | 1201210013223 |
11 | 423480811a20 |
12 | 1749769776b3 |
13 | 893731a6a6c |
14 | 421d3103263 |
15 | 213a6052ed3 |
hex | 117adb23627 |
1201210013223 has 16 divisors (see below), whose sum is σ = 1941349516800. Its totient is φ = 728006068440.
The previous prime is 1201210013219. The next prime is 1201210013233. The reversal of 1201210013223 is 3223100121021.
It is not a de Polignac number, because 1201210013223 - 22 = 1201210013219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201210013196 and 1201210013205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201210013203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2022238783 + ... + 2022239376.
It is an arithmetic number, because the mean of its divisors is an integer number (121334344800).
Almost surely, 21201210013223 is an apocalyptic number.
1201210013223 is a deficient number, since it is larger than the sum of its proper divisors (740139503577).
1201210013223 is a wasteful number, since it uses less digits than its factorization.
1201210013223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4044478179 (or 4044478173 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1201210013223 its reverse (3223100121021), we get a palindrome (4424310134244).
The spelling of 1201210013223 in words is "one trillion, two hundred one billion, two hundred ten million, thirteen thousand, two hundred twenty-three".
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