12012100202201 has 4 divisors (see below), whose sum is σ = 13104109311504. Its totient is φ = 10920091092900.

The previous prime is 12012100202177. The next prime is 12012100202243. The reversal of 12012100202201 is 10220200121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-12012100202201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12012100202251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546004554635 + ... + 546004554656.

It is an arithmetic number, because the mean of its divisors is an integer number (3276027327876).

Almost surely, 2^{12012100202201} is an apocalyptic number.

12012100202201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12012100202201 is a deficient number, since it is larger than the sum of its proper divisors (1092009109303).

12012100202201 is a wasteful number, since it uses less digits than its factorization.

12012100202201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1092009109302.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 12012100202201 its reverse (10220200121021), we get a palindrome (22232300323222).

The spelling of 12012100202201 in words is "twelve trillion, twelve billion, one hundred million, two hundred two thousand, two hundred one".