Base | Representation |
---|---|
bin | 10001011110101101101… |
… | …100100101100010001111 |
3 | 11020211112101120121011020 |
4 | 101132231230211202033 |
5 | 124140034231201111 |
6 | 2315454523325223 |
7 | 152533050502035 |
oct | 21365554454217 |
9 | 4224471517136 |
10 | 1201210022031 |
11 | 4234808185a8 |
12 | 174976980813 |
13 | 893731aaa86 |
14 | 421d3106555 |
15 | 213a6055906 |
hex | 117adb2588f |
1201210022031 has 16 divisors (see below), whose sum is σ = 1671306925056. Its totient is φ = 765962325216.
The previous prime is 1201210022017. The next prime is 1201210022053. The reversal of 1201210022031 is 1302200121021.
It is not a de Polignac number, because 1201210022031 - 214 = 1201210005647 is a prime.
It is a super-2 number, since 2×12012100220312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1201210022031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201210022011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1797381 + ... + 2373393.
It is an arithmetic number, because the mean of its divisors is an integer number (104456682816).
Almost surely, 21201210022031 is an apocalyptic number.
1201210022031 is a deficient number, since it is larger than the sum of its proper divisors (470096903025).
1201210022031 is a wasteful number, since it uses less digits than its factorization.
1201210022031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606262.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 1201210022031 its reverse (1302200121021), we get a palindrome (2503410143052).
The spelling of 1201210022031 in words is "one trillion, two hundred one billion, two hundred ten million, twenty-two thousand, thirty-one".
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