Base | Representation |
---|---|
bin | 10001011110101101101… |
… | …100111101110001010111 |
3 | 11020211112101202122022222 |
4 | 101132231230331301113 |
5 | 124140034242340203 |
6 | 2315454525412555 |
7 | 152533051364333 |
oct | 21365554756127 |
9 | 4224471678288 |
10 | 1201210121303 |
11 | 423480886145 |
12 | 174976a0a15b |
13 | 8937321400a |
14 | 421d31307c3 |
15 | 213a6075038 |
hex | 117adb3dc57 |
1201210121303 has 4 divisors (see below), whose sum is σ = 1201220006400. Its totient is φ = 1201200236208.
The previous prime is 1201210121219. The next prime is 1201210121329. The reversal of 1201210121303 is 3031210121021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1201210121303 - 220 = 1201209072727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201210121333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4757975 + ... + 5004072.
It is an arithmetic number, because the mean of its divisors is an integer number (300305001600).
Almost surely, 21201210121303 is an apocalyptic number.
1201210121303 is a deficient number, since it is larger than the sum of its proper divisors (9885097).
1201210121303 is an equidigital number, since it uses as much as digits as its factorization.
1201210121303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9885096.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1201210121303 its reverse (3031210121021), we get a palindrome (4232420242324).
The spelling of 1201210121303 in words is "one trillion, two hundred one billion, two hundred ten million, one hundred twenty-one thousand, three hundred three".
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