12012110113 has 4 divisors (see below), whose sum is σ = 12399597568. Its totient is φ = 11624622660.

The previous prime is 12012110063. The next prime is 12012110141. The reversal of 12012110113 is 31101121021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31101121021 = 29 ⋅1072452449.

It is a cyclic number.

It is not a de Polignac number, because 12012110113 - 2²⁹ = 11475239201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012110093 and 12012110102.

It is not an unprimeable number, because it can be changed into a prime (12012110183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193743681 + ... + 193743742.

It is an arithmetic number, because the mean of its divisors is an integer number (3099899392).

Almost surely, 2^12012110113 is an apocalyptic number.

It is an amenable number.

12012110113 is a deficient number, since it is larger than the sum of its proper divisors (387487455).

12012110113 is an equidigital number, since it uses as much as digits as its factorization.

12012110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 387487454.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 12012110113 its reverse (31101121021), we get a palindrome (43113231134).

The spelling of 12012110113 in words is "twelve billion, twelve million, one hundred ten thousand, one hundred thirteen".