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12012111100133 = 31387487454843
BaseRepresentation
bin1010111011001100100110…
…0111010111100011100101
31120112100100200020201212122
42232303021213113203211
53033301300420201013
641314142044555325
72346563211452234
oct256631147274345
946470320221778
1012012111100133
113911342619671
12142003b852b45
13691977883421
142d756427ab1b
1515c6e12d9a08
hexaecc99d78e5

12012111100133 has 4 divisors (see below), whose sum is σ = 12399598555008. Its totient is φ = 11624623645260.

The previous prime is 12012111100123. The next prime is 12012111100163. The reversal of 12012111100133 is 33100111121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12012111100133 - 222 = 12012106905829 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012111100103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193743727391 + ... + 193743727452.

It is an arithmetic number, because the mean of its divisors is an integer number (3099899638752).

Almost surely, 212012111100133 is an apocalyptic number.

It is an amenable number.

12012111100133 is a deficient number, since it is larger than the sum of its proper divisors (387487454875).

12012111100133 is an equidigital number, since it uses as much as digits as its factorization.

12012111100133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 387487454874.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 12012111100133 its reverse (33100111121021), we get a palindrome (45112222221154).

The spelling of 12012111100133 in words is "twelve trillion, twelve billion, one hundred eleven million, one hundred thousand, one hundred thirty-three".

Divisors: 1 31 387487454843 12012111100133