120121120003 has 4 divisors (see below), whose sum is σ = 120267431568. Its totient is φ = 119974808440.

The previous prime is 120121119997. The next prime is 120121120019. The reversal of 120121120003 is 300021121021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300021121021 = 251 ⋅1195303271.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120121120003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120121120073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73154551 + ... + 73156192.

It is an arithmetic number, because the mean of its divisors is an integer number (30066857892).

Almost surely, 2^120121120003 is an apocalyptic number.

120121120003 is a deficient number, since it is larger than the sum of its proper divisors (146311565).

120121120003 is an equidigital number, since it uses as much as digits as its factorization.

120121120003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146311564.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 120121120003 its reverse (300021121021), we get a palindrome (420142241024).

The spelling of 120121120003 in words is "one hundred twenty billion, one hundred twenty-one million, one hundred twenty thousand, three".