12012113121231 has 4 divisors (see below), whose sum is σ = 16016150828312. Its totient is φ = 8008075414152.

The previous prime is 12012113121221. The next prime is 12012113121269. The reversal of 12012113121231 is 13212131121021.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12012113121231 - 2⁷ = 12012113121103 is a prime.

It is a super-2 number, since 2×12012113121231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012113121198 and 12012113121207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012113121221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002018853536 + ... + 2002018853541.

It is an arithmetic number, because the mean of its divisors is an integer number (4004037707078).

Almost surely, 2^{12012113121231} is an apocalyptic number.

12012113121231 is a deficient number, since it is larger than the sum of its proper divisors (4004037707081).

12012113121231 is an equidigital number, since it uses as much as digits as its factorization.

12012113121231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4004037707080.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 12012113121231 its reverse (13212131121021), we get a palindrome (25224244242252).

The spelling of 12012113121231 in words is "twelve trillion, twelve billion, one hundred thirteen million, one hundred twenty-one thousand, two hundred thirty-one".