12012115314553 has 4 divisors (see below), whose sum is σ = 12013159585408. Its totient is φ = 12011071043700.

The previous prime is 12012115314503. The next prime is 12012115314559. The reversal of 12012115314553 is 35541351121021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12012115314553 - 2¹³ = 12012115306361 is a prime.

It is a super-3 number, since 3×12012115314553³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12012115314559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 522118173 + ... + 522141178.

It is an arithmetic number, because the mean of its divisors is an integer number (3003289896352).

Almost surely, 2^{12012115314553} is an apocalyptic number.

It is an amenable number.

12012115314553 is a deficient number, since it is larger than the sum of its proper divisors (1044270855).

12012115314553 is a wasteful number, since it uses less digits than its factorization.

12012115314553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1044270854.

The product of its (nonzero) digits is 18000, while the sum is 34.

Adding to 12012115314553 its reverse (35541351121021), we get a palindrome (47553466435574).

The spelling of 12012115314553 in words is "twelve trillion, twelve billion, one hundred fifteen million, three hundred fourteen thousand, five hundred fifty-three".