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120121221003103 = 1031116509428713
BaseRepresentation
bin11011010011111111100110…
…101101010011011101011111
3120202022110212102111000211001
4123103333212231103131133
5111221031230034044403
61103250532131411131
734205320556542315
oct3323774655233537
9522273772430731
10120121221003103
113530213a780001
1211580369a53aa7
1352044c8580388
142193c806120b5
15dd49668e4c1d
hex6d3fe6b5375f

120121221003103 has 4 divisors (see below), whose sum is σ = 120237730432848. Its totient is φ = 120004711573360.

The previous prime is 120121221002983. The next prime is 120121221003131. The reversal of 120121221003103 is 301300122121021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120121221003103 - 213 = 120121220994911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120121221009103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58254713326 + ... + 58254715387.

It is an arithmetic number, because the mean of its divisors is an integer number (30059432608212).

Almost surely, 2120121221003103 is an apocalyptic number.

120121221003103 is a deficient number, since it is larger than the sum of its proper divisors (116509429745).

120121221003103 is a wasteful number, since it uses less digits than its factorization.

120121221003103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116509429744.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 120121221003103 its reverse (301300122121021), we get a palindrome (421421343124124).

The spelling of 120121221003103 in words is "one hundred twenty trillion, one hundred twenty-one billion, two hundred twenty-one million, three thousand, one hundred three".

Divisors: 1 1031 116509428713 120121221003103