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120121222121120 = 255117313722972971
BaseRepresentation
bin11011010011111111100110…
…110001100100011010100000
3120202022110212111120211110002
4123103333212301210122200
5111221031230330333440
61103250532211355132
734205320602206663
oct3323774661443240
9522273774524402
10120121222121120
1135302140373a90
121158036a2b2aa8
1352044c888221c
142193c808236da
15dd4966a66115
hex6d3fe6c646a0

120121222121120 has 384 divisors, whose sum is σ = 316360811918592. Its totient is φ = 42734606745600.

The previous prime is 120121222121083. The next prime is 120121222121129. The reversal of 120121222121120 is 21121222121021.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 120121222121092 and 120121222121101.

It is not an unprimeable number, because it can be changed into a prime (120121222121129) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 40431241235 + ... + 40431244205.

It is an arithmetic number, because the mean of its divisors is an integer number (823856281038).

Almost surely, 2120121222121120 is an apocalyptic number.

120121222121120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120121222121120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158180405959296).

120121222121120 is an abundant number, since it is smaller than the sum of its proper divisors (196239589797472).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120121222121120 is a wasteful number, since it uses less digits than its factorization.

120121222121120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5504 (or 5496 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 120121222121120 its reverse (21121222121021), we get a palindrome (141242444242141).

Subtracting from 120121222121120 its reverse (21121222121021), we obtain a palindrome (99000000000099).

It can be divided in two parts, 1201212 and 22121120, that added together give a palindrome (23322332).

The spelling of 120121222121120 in words is "one hundred twenty trillion, one hundred twenty-one billion, two hundred twenty-two million, one hundred twenty-one thousand, one hundred twenty".