12012132332131 has 4 divisors (see below), whose sum is σ = 12012447906000. Its totient is φ = 12011816758264.

The previous prime is 12012132332063. The next prime is 12012132332149. The reversal of 12012132332131 is 13123323121021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12012132332131 is a prime.

It is a super-3 number, since 3×12012132332131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012132332096 and 12012132332105.

It is not an unprimeable number, because it can be changed into a prime (12012132332731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157729831 + ... + 157805968.

It is an arithmetic number, because the mean of its divisors is an integer number (3003111976500).

Almost surely, 2^{12012132332131} is an apocalyptic number.

12012132332131 is a deficient number, since it is larger than the sum of its proper divisors (315573869).

12012132332131 is an equidigital number, since it uses as much as digits as its factorization.

12012132332131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 315573868.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12012132332131 its reverse (13123323121021), we get a palindrome (25135455453152).

The spelling of 12012132332131 in words is "twelve trillion, twelve billion, one hundred thirty-two million, three hundred thirty-two thousand, one hundred thirty-one".