12012211200113 has 4 divisors (see below), whose sum is σ = 12020256888948. Its totient is φ = 12004165511280.

The previous prime is 12012211200107. The next prime is 12012211200133. The reversal of 12012211200113 is 31100211221021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4193124434944 + 7819086765169 = 2047712^2 + 2796263^2 .

It is a cyclic number.

It is not a de Polignac number, because 12012211200113 - 2²⁴ = 12012194422897 is a prime.

It is a super-2 number, since 2×12012211200113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12012211200091 and 12012211200100.

It is not an unprimeable number, because it can be changed into a prime (12012211200133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4022842178 + ... + 4022845163.

It is an arithmetic number, because the mean of its divisors is an integer number (3005064222237).

Almost surely, 2^{12012211200113} is an apocalyptic number.

It is an amenable number.

12012211200113 is a deficient number, since it is larger than the sum of its proper divisors (8045688835).

12012211200113 is an equidigital number, since it uses as much as digits as its factorization.

12012211200113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8045688834.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 12012211200113 its reverse (31100211221021), we get a palindrome (43112422421134).

The spelling of 12012211200113 in words is "twelve trillion, twelve billion, two hundred eleven million, two hundred thousand, one hundred thirteen".