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120123001023 = 340041000341
BaseRepresentation
bin110111111011111100…
…0111000100010111111
3102111001120121201011220
41233313320320202333
53432002442013043
6131103404444423
711451521442654
oct1576770704277
9374046551156
10120123001023
1146a42336663
121b344b49713
13b43482223c
145b57803c2b
1531d0ba0483
hex1bf7e388bf

120123001023 has 4 divisors (see below), whose sum is σ = 160164001368. Its totient is φ = 80082000680.

The previous prime is 120123001003. The next prime is 120123001039. The reversal of 120123001023 is 320100321021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120123001023 - 221 = 120120903871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120123000993 and 120123001011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120123001003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20020500168 + ... + 20020500173.

It is an arithmetic number, because the mean of its divisors is an integer number (40041000342).

Almost surely, 2120123001023 is an apocalyptic number.

120123001023 is a deficient number, since it is larger than the sum of its proper divisors (40041000345).

120123001023 is an equidigital number, since it uses as much as digits as its factorization.

120123001023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40041000344.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 120123001023 its reverse (320100321021), we get a palindrome (440223322044).

The spelling of 120123001023 in words is "one hundred twenty billion, one hundred twenty-three million, one thousand, twenty-three".

Divisors: 1 3 40041000341 120123001023