Base | Representation |
---|---|
bin | 100011110011001… |
… | …0101110011101101 |
3 | 10002201022222002001 |
4 | 1013212111303231 |
5 | 4430003430013 |
6 | 315110332301 |
7 | 41524212262 |
oct | 10746256355 |
9 | 3081288061 |
10 | 1201233133 |
11 | 567079261 |
12 | 29635a091 |
13 | 161b36849 |
14 | b5771269 |
15 | 706d0ddd |
hex | 47995ced |
1201233133 has 4 divisors (see below), whose sum is σ = 1202718780. Its totient is φ = 1199747488.
The previous prime is 1201233113. The next prime is 1201233139. The reversal of 1201233133 is 3313321021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1062629604 + 138603529 = 32598^2 + 11773^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201233133 - 25 = 1201233101 is a prime.
It is a super-2 number, since 2×12012331332 = 2885922079633991378, which contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1201233133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201233139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 741610 + ... + 743227.
It is an arithmetic number, because the mean of its divisors is an integer number (300679695).
Almost surely, 21201233133 is an apocalyptic number.
It is an amenable number.
1201233133 is a deficient number, since it is larger than the sum of its proper divisors (1485647).
1201233133 is an equidigital number, since it uses as much as digits as its factorization.
1201233133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1485646.
The product of its (nonzero) digits is 324, while the sum is 19.
The square root of 1201233133 is about 34658.8103229179. The cubic root of 1201233133 is about 1063.0224443896.
Adding to 1201233133 its reverse (3313321021), we get a palindrome (4514554154).
It can be divided in two parts, 120123 and 3133, that added together give a triangular number (123256 = T496).
The spelling of 1201233133 in words is "one billion, two hundred one million, two hundred thirty-three thousand, one hundred thirty-three".
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