Base | Representation |
---|---|
bin | 10110010111111110… |
… | …11100110100011011 |
3 | 1011000011100020011010 |
4 | 23023333130310123 |
5 | 144100124430210 |
6 | 5303550105003 |
7 | 603451140603 |
oct | 131377346433 |
9 | 34004306133 |
10 | 12012342555 |
11 | 5104721834 |
12 | 23b2aab163 |
13 | 1195896705 |
14 | 81d511c03 |
15 | 4a48ac920 |
hex | 2cbfdcd1b |
12012342555 has 16 divisors (see below), whose sum is σ = 19406350080. Its totient is φ = 6344382048.
The previous prime is 12012342553. The next prime is 12012342571. The reversal of 12012342555 is 55524321021.
It is not a de Polignac number, because 12012342555 - 21 = 12012342553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12012342553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3885945 + ... + 3889034.
It is an arithmetic number, because the mean of its divisors is an integer number (1212896880).
Almost surely, 212012342555 is an apocalyptic number.
12012342555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12012342555 is a deficient number, since it is larger than the sum of its proper divisors (7394007525).
12012342555 is a wasteful number, since it uses less digits than its factorization.
12012342555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7775090.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 12012342555 its reverse (55524321021), we get a palindrome (67536663576).
The spelling of 12012342555 in words is "twelve billion, twelve million, three hundred forty-two thousand, five hundred fifty-five".
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