Base | Representation |
---|---|
bin | 110111111100000000… |
… | …0111100101010010111 |
3 | 102111001201121010001111 |
4 | 1233320000330222113 |
5 | 3432004012140111 |
6 | 131103522035451 |
7 | 11451545426155 |
oct | 1577000745227 |
9 | 374051533044 |
10 | 120125115031 |
11 | 46a4354a979 |
12 | 1b3457a8b87 |
13 | b4350b252c |
14 | 5b57bd43d5 |
15 | 31d0e6ba21 |
hex | 1bf803ca97 |
120125115031 has 4 divisors (see below), whose sum is σ = 120130949232. Its totient is φ = 120119280832.
The previous prime is 120125115023. The next prime is 120125115049. The reversal of 120125115031 is 130511521021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120125115031 - 23 = 120125115023 is a prime.
It is a super-2 number, since 2×1201251150312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120125114993 and 120125115011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120125115931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2886106 + ... + 2927431.
It is an arithmetic number, because the mean of its divisors is an integer number (30032737308).
Almost surely, 2120125115031 is an apocalyptic number.
120125115031 is a deficient number, since it is larger than the sum of its proper divisors (5834201).
120125115031 is an equidigital number, since it uses as much as digits as its factorization.
120125115031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5834200.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 120125115031 its reverse (130511521021), we get a palindrome (250636636052).
The spelling of 120125115031 in words is "one hundred twenty billion, one hundred twenty-five million, one hundred fifteen thousand, thirty-one".
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