Base | Representation |
---|---|
bin | 10110011000000011… |
… | …11101100100010111 |
3 | 1011000012120200100100 |
4 | 23030001331210113 |
5 | 144100312012413 |
6 | 5304012145143 |
7 | 603456552324 |
oct | 131401754427 |
9 | 34005520310 |
10 | 12013000983 |
11 | 5105031495 |
12 | 23b31681b3 |
13 | 1195a67309 |
14 | 81d643b4b |
15 | 4a498ca73 |
hex | 2cc07d917 |
12013000983 has 6 divisors (see below), whose sum is σ = 17352112544. Its totient is φ = 8008667316.
The previous prime is 12013000981. The next prime is 12013000997. The reversal of 12013000983 is 38900031021.
12013000983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12013000983 - 21 = 12013000981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013000981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 667388935 + ... + 667388952.
Almost surely, 212013000983 is an apocalyptic number.
12013000983 is a deficient number, since it is larger than the sum of its proper divisors (5339111561).
12013000983 is a wasteful number, since it uses less digits than its factorization.
12013000983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1334777893 (or 1334777890 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 27.
The spelling of 12013000983 in words is "twelve billion, thirteen million, nine hundred eighty-three", and thus it is an aban number.
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