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120130010055025 = 5216728773655103
BaseRepresentation
bin11011010100000111110010…
…100100111000000101110001
3120202100022112221122010110121
4123110013302210320011301
5111221202230033230100
61103254544215330241
734206051431340355
oct3324076244700561
9522308487563417
10120130010055025
113530593a990883
1211582001380981
135205299412109
1421944759d5465
15dd4ccd30351a
hex6d41f2938171

120130010055025 has 12 divisors (see below), whose sum is σ = 149853195781632. Its totient is φ = 95528534938640.

The previous prime is 120130010055017. The next prime is 120130010055061. The reversal of 120130010055025 is 520550010031021.

It is not a de Polignac number, because 120130010055025 - 23 = 120130010055017 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14386823377 + ... + 14386831726.

It is an arithmetic number, because the mean of its divisors is an integer number (12487766315136).

Almost surely, 2120130010055025 is an apocalyptic number.

It is an amenable number.

120130010055025 is a deficient number, since it is larger than the sum of its proper divisors (29723185726607).

120130010055025 is a wasteful number, since it uses less digits than its factorization.

120130010055025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28773655280 (or 28773655275 counting only the distinct ones).

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 120130010055025 its reverse (520550010031021), we get a palindrome (640680020086046).

The spelling of 120130010055025 in words is "one hundred twenty trillion, one hundred thirty billion, ten million, fifty-five thousand, twenty-five".

Divisors: 1 5 25 167 835 4175 28773655103 143868275515 719341377575 4805200402201 24026002011005 120130010055025