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12013002220231 = 19632263274749
BaseRepresentation
bin1010111011001111111010…
…1110101110001011000111
31120112102122210001022211201
42232303332232232023013
53033310112032021411
641314410320443331
72346624252035065
oct256637656561307
946472583038751
1012013002220231
11391175a636361
12142024a179547
13691a8a38b01c
142d760a765035
1515c7446603c1
hexaecfebae2c7

12013002220231 has 4 divisors (see below), whose sum is σ = 12645265495000. Its totient is φ = 11380738945464.

The previous prime is 12013002220229. The next prime is 12013002220237. The reversal of 12013002220231 is 13202220031021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013002220231 - 21 = 12013002220229 is a prime.

It is a super-2 number, since 2×120130022202312 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 632263274749 = 12013002220231 / (1 + 2 + 0 + 1 + 3 + 0 + 0 + 2 + 2 + 2 + 0 + 2 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013002220199 and 12013002220208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013002220237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316131637356 + ... + 316131637393.

It is an arithmetic number, because the mean of its divisors is an integer number (3161316373750).

Almost surely, 212013002220231 is an apocalyptic number.

12013002220231 is a deficient number, since it is larger than the sum of its proper divisors (632263274769).

12013002220231 is an equidigital number, since it uses as much as digits as its factorization.

12013002220231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 632263274768.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 12013002220231 its reverse (13202220031021), we get a palindrome (25215222251252).

The spelling of 12013002220231 in words is "twelve trillion, thirteen billion, two million, two hundred twenty thousand, two hundred thirty-one".

Divisors: 1 19 632263274749 12013002220231