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1201301135 = 5240260227
BaseRepresentation
bin100011110011010…
…0110011010001111
310002201110102100122
41013212212122033
54430013114020
6315112015155
741524614446
oct10746463217
93081412318
101201301135
11567115361
122963914bb
13161b5b798
14b578bd5d
15706e6125
hex479a668f

1201301135 has 4 divisors (see below), whose sum is σ = 1441561368. Its totient is φ = 961040904.

The previous prime is 1201301113. The next prime is 1201301147. The reversal of 1201301135 is 5311031021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5311031021 = 36311462691.

It is a cyclic number.

It is not a de Polignac number, because 1201301135 - 212 = 1201297039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120130109 + ... + 120130118.

It is an arithmetic number, because the mean of its divisors is an integer number (360390342).

Almost surely, 21201301135 is an apocalyptic number.

1201301135 is a deficient number, since it is larger than the sum of its proper divisors (240260233).

1201301135 is an equidigital number, since it uses as much as digits as its factorization.

1201301135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 240260232.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 1201301135 is about 34659.7913294353. The cubic root of 1201301135 is about 1063.0425033014.

Adding to 1201301135 its reverse (5311031021), we get a palindrome (6512332156).

The spelling of 1201301135 in words is "one billion, two hundred one million, three hundred one thousand, one hundred thirty-five".

Divisors: 1 5 240260227 1201301135