Base | Representation |
---|---|
bin | 10001011110110011001… |
… | …011111111010011000111 |
3 | 11020211202210220200101200 |
4 | 101132303023333103013 |
5 | 124140231321440403 |
6 | 2315512013553543 |
7 | 152535246465612 |
oct | 21366313772307 |
9 | 4224683820350 |
10 | 1201302140103 |
11 | 42351881623a |
12 | 1749a17a58b3 |
13 | 893892c1b00 |
14 | 42201445179 |
15 | 213ae19eca3 |
hex | 117b32ff4c7 |
1201302140103 has 72 divisors (see below), whose sum is σ = 1890432230544. Its totient is φ = 734761497600.
The previous prime is 1201302140099. The next prime is 1201302140111. The reversal of 1201302140103 is 3010412031021.
1201302140103 is a `hidden beast` number, since 120 + 1 + 302 + 140 + 103 = 666.
It is not a de Polignac number, because 1201302140103 - 22 = 1201302140099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201302140153) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 206370933 + ... + 206376753.
It is an arithmetic number, because the mean of its divisors is an integer number (26256003202).
Almost surely, 21201302140103 is an apocalyptic number.
1201302140103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1201302140103 is a deficient number, since it is larger than the sum of its proper divisors (689130090441).
1201302140103 is a wasteful number, since it uses less digits than its factorization.
1201302140103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6657 (or 6641 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1201302140103 its reverse (3010412031021), we get a palindrome (4211714171124).
The spelling of 1201302140103 in words is "one trillion, two hundred one billion, three hundred two million, one hundred forty thousand, one hundred three".
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