120131000001013 has 4 divisors (see below), whose sum is σ = 124273448276940. Its totient is φ = 115988551725088.

The previous prime is 120131000000969. The next prime is 120131000001043. The reversal of 120131000001013 is 310100000131021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 95542472823889 + 24588527177124 = 9774583^2 + 4958682^2 .

It is a cyclic number.

It is not a de Polignac number, because 120131000001013 - 2¹³ = 120130999992821 is a prime.

It is a super-2 number, since 2×120131000001013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120131000000984 and 120131000001002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131000001043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2071224137920 + ... + 2071224137977.

It is an arithmetic number, because the mean of its divisors is an integer number (31068362069235).

Almost surely, 2^{120131000001013} is an apocalyptic number.

It is an amenable number.

120131000001013 is a deficient number, since it is larger than the sum of its proper divisors (4142448275927).

120131000001013 is an equidigital number, since it uses as much as digits as its factorization.

120131000001013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4142448275926.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 120131000001013 its reverse (310100000131021), we get a palindrome (430231000132034).

The spelling of 120131000001013 in words is "one hundred twenty trillion, one hundred thirty-one billion, one thousand, thirteen".