Base | Representation |
---|---|
bin | 10110011000000100… |
… | …10110001110110011 |
3 | 1011000012202210220211 |
4 | 23030002112032303 |
5 | 144100323231003 |
6 | 5304014244551 |
7 | 603460453000 |
oct | 131402261663 |
9 | 34005683824 |
10 | 12013102003 |
11 | 51050a0381 |
12 | 23b31b6757 |
13 | 1195aa12a6 |
14 | 81d66c8a7 |
15 | 4a49ac96d |
hex | 2cc0963b3 |
12013102003 has 24 divisors (see below), whose sum is σ = 14882132000. Its totient is φ = 9691161984.
The previous prime is 12013102001. The next prime is 12013102103. The reversal of 12013102003 is 30020131021.
It is not a de Polignac number, because 12013102003 - 21 = 12013102001 is a prime.
It is a super-2 number, since 2×120131020032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013102001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38533 + ... + 159721.
Almost surely, 212013102003 is an apocalyptic number.
12013102003 is a deficient number, since it is larger than the sum of its proper divisors (2869029997).
12013102003 is an equidigital number, since it uses as much as digits as its factorization.
12013102003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121244 (or 121213 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 12013102003 its reverse (30020131021), we get a palindrome (42033233024).
The spelling of 12013102003 in words is "twelve billion, thirteen million, one hundred two thousand, three".
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