Search a number
-
+
12013102102002 = 232002183683667
BaseRepresentation
bin1010111011010000010010…
…1011101111010111110010
31120112102220201222211212120
42232310010223233113302
53033310313114231002
641314424245335110
72346626604025431
oct256640453572762
946472821884776
1012013102102002
113911800a56a81
121420277707496
13691aa4c8ca71
142d7619b25118
1515c74d2decbc
hexaed04aef5f2

12013102102002 has 8 divisors (see below), whose sum is σ = 24026204204016. Its totient is φ = 4004367367332.

The previous prime is 12013102101887. The next prime is 12013102102007. The reversal of 12013102102002 is 20020120131021.

It is a sphenic number, since it is the product of 3 distinct primes.

12013102102002 is an admirable number.

It is a super-2 number, since 2×120131021020022 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12013102102007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001091841828 + ... + 1001091841839.

It is an arithmetic number, because the mean of its divisors is an integer number (3003275525502).

Almost surely, 212013102102002 is an apocalyptic number.

12013102102002 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013102102002 is a wasteful number, since it uses less digits than its factorization.

12013102102002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2002183683672.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12013102102002 its reverse (20020120131021), we get a palindrome (32033222233023).

The spelling of 12013102102002 in words is "twelve trillion, thirteen billion, one hundred two million, one hundred two thousand, two".

Divisors: 1 2 3 6 2002183683667 4004367367334 6006551051001 12013102102002