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12013102131 = 34197667497
BaseRepresentation
bin10110011000000100…
…10110010000110011
31011000012202211002120
423030002112100303
5144100323232011
65304014245323
7603460453242
oct131402262063
934005684076
1012013102131
1151050a0488
1223b31b6843
131195aa1374
1481d66c959
154a49aca06
hex2cc096433

12013102131 has 8 divisors (see below), whose sum is σ = 16408139664. Its totient is φ = 7813399680.

The previous prime is 12013102121. The next prime is 12013102201. The reversal of 12013102131 is 13120131021.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12013102131 - 29 = 12013101619 is a prime.

It is a super-2 number, since 2×120131021312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12013102131.

It is not an unprimeable number, because it can be changed into a prime (12013102121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48833626 + ... + 48833871.

It is an arithmetic number, because the mean of its divisors is an integer number (2051017458).

Almost surely, 212013102131 is an apocalyptic number.

12013102131 is a deficient number, since it is larger than the sum of its proper divisors (4395037533).

12013102131 is an equidigital number, since it uses as much as digits as its factorization.

12013102131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97667541.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 12013102131 its reverse (13120131021), we get a palindrome (25133233152).

The spelling of 12013102131 in words is "twelve billion, thirteen million, one hundred two thousand, one hundred thirty-one".

Divisors: 1 3 41 123 97667497 293002491 4004367377 12013102131