1201311001203 has 4 divisors (see below), whose sum is σ = 1601748001608. Its totient is φ = 800874000800.

The previous prime is 1201311001193. The next prime is 1201311001213. The reversal of 1201311001203 is 3021001131021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1201311001193) and next prime (1201311001213).

It is a cyclic number.

It is not a de Polignac number, because 1201311001203 - 2⁹ = 1201311000691 is a prime.

It is a super-2 number, since 2×1201311001203² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1201311001213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200218500198 + ... + 200218500203.

It is an arithmetic number, because the mean of its divisors is an integer number (400437000402).

Almost surely, 2^{1201311001203} is an apocalyptic number.

1201311001203 is a deficient number, since it is larger than the sum of its proper divisors (400437000405).

1201311001203 is an equidigital number, since it uses as much as digits as its factorization.

1201311001203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400437000404.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1201311001203 its reverse (3021001131021), we get a palindrome (4222312132224).

The spelling of 1201311001203 in words is "one trillion, two hundred one billion, three hundred eleven million, one thousand, two hundred three".