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1201311214111 = 1817093793563
BaseRepresentation
bin10001011110110011101…
…110100110101000011111
311020211210102222200121001
4101132303232212220133
5124140241132322421
62315512540251131
7152535416560501
oct21366356465037
94224712880531
101201311214111
11423522953718
121749a4840aa7
138938b14b048
1442202727d71
15213aed93691
hex117b3ba6a1f

1201311214111 has 8 divisors (see below), whose sum is σ = 1207978231824. Its totient is φ = 1194644525760.

The previous prime is 1201311214079. The next prime is 1201311214123. The reversal of 1201311214111 is 1114121131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1201311214111 - 25 = 1201311214079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201311214151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12792816 + ... + 12886378.

It is an arithmetic number, because the mean of its divisors is an integer number (150997278978).

Almost surely, 21201311214111 is an apocalyptic number.

1201311214111 is a deficient number, since it is larger than the sum of its proper divisors (6667017713).

1201311214111 is an equidigital number, since it uses as much as digits as its factorization.

1201311214111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164681.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1201311214111 its reverse (1114121131021), we get a palindrome (2315432345132).

The spelling of 1201311214111 in words is "one trillion, two hundred one billion, three hundred eleven million, two hundred fourteen thousand, one hundred eleven".

Divisors: 1 181 70937 93563 12839597 16934903 6637078531 1201311214111