Base | Representation |
---|---|
bin | 10001011110110011101… |
… | …110100110101000011111 |
3 | 11020211210102222200121001 |
4 | 101132303232212220133 |
5 | 124140241132322421 |
6 | 2315512540251131 |
7 | 152535416560501 |
oct | 21366356465037 |
9 | 4224712880531 |
10 | 1201311214111 |
11 | 423522953718 |
12 | 1749a4840aa7 |
13 | 8938b14b048 |
14 | 42202727d71 |
15 | 213aed93691 |
hex | 117b3ba6a1f |
1201311214111 has 8 divisors (see below), whose sum is σ = 1207978231824. Its totient is φ = 1194644525760.
The previous prime is 1201311214079. The next prime is 1201311214123. The reversal of 1201311214111 is 1114121131021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1201311214111 - 25 = 1201311214079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201311214151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12792816 + ... + 12886378.
It is an arithmetic number, because the mean of its divisors is an integer number (150997278978).
Almost surely, 21201311214111 is an apocalyptic number.
1201311214111 is a deficient number, since it is larger than the sum of its proper divisors (6667017713).
1201311214111 is an equidigital number, since it uses as much as digits as its factorization.
1201311214111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164681.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 1201311214111 its reverse (1114121131021), we get a palindrome (2315432345132).
The spelling of 1201311214111 in words is "one trillion, two hundred one billion, three hundred eleven million, two hundred fourteen thousand, one hundred eleven".
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