12013113222403 has 4 divisors (see below), whose sum is σ = 12027639357720. Its totient is φ = 11998587087088.

The previous prime is 12013113222391. The next prime is 12013113222427. The reversal of 12013113222403 is 30422231131021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12013113222403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013113222433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7263066418 + ... + 7263068071.

It is an arithmetic number, because the mean of its divisors is an integer number (3006909839430).

Almost surely, 2^{12013113222403} is an apocalyptic number.

12013113222403 is a deficient number, since it is larger than the sum of its proper divisors (14526135317).

12013113222403 is an equidigital number, since it uses as much as digits as its factorization.

12013113222403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14526135316.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 12013113222403 its reverse (30422231131021), we get a palindrome (42435344353424).

The spelling of 12013113222403 in words is "twelve trillion, thirteen billion, one hundred thirteen million, two hundred twenty-two thousand, four hundred three".