120131213011133 has 4 divisors (see below), whose sum is σ = 120390675674688. Its totient is φ = 119871750347580.

The previous prime is 120131213011129. The next prime is 120131213011163. The reversal of 120131213011133 is 331110312131021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120131213011133 - 2² = 120131213011129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120131213011099 and 120131213011108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131213011163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129731331083 + ... + 129731332008.

It is an arithmetic number, because the mean of its divisors is an integer number (30097668918672).

Almost surely, 2^{120131213011133} is an apocalyptic number.

It is an amenable number.

120131213011133 is a deficient number, since it is larger than the sum of its proper divisors (259462663555).

120131213011133 is an equidigital number, since it uses as much as digits as its factorization.

120131213011133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259462663554.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 120131213011133 its reverse (331110312131021), we get a palindrome (451241525142154).

The spelling of 120131213011133 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred thirteen million, eleven thousand, one hundred thirty-three".