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12013130011411 = 127222142589633
BaseRepresentation
bin1010111011010000011001…
…0110001101001100010011
31120112102222200111210101101
42232310012112031030103
53033310342240331121
641314431123445231
72346630363166114
oct256640626151423
946472880453341
1012013130011411
113911815789801
121420284b26817
13691aaa9b22c9
142d761d70c20b
1515c7509a4491
hexaed0658d313

12013130011411 has 8 divisors (see below), whose sum is σ = 12113173343744. Its totient is φ = 11913171863040.

The previous prime is 12013130011327. The next prime is 12013130011447. The reversal of 12013130011411 is 11411003131021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12013130011411 - 215 = 12013129978643 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013130011711) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21012750 + ... + 21576883.

It is an arithmetic number, because the mean of its divisors is an integer number (1514146667968).

Almost surely, 212013130011411 is an apocalyptic number.

12013130011411 is a deficient number, since it is larger than the sum of its proper divisors (100043332333).

12013130011411 is a wasteful number, since it uses less digits than its factorization.

12013130011411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42591981.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 12013130011411 its reverse (11411003131021), we get a palindrome (23424133142432).

The spelling of 12013130011411 in words is "twelve trillion, thirteen billion, one hundred thirty million, eleven thousand, four hundred eleven".

Divisors: 1 127 2221 282067 42589633 5408883391 94591574893 12013130011411